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我试图从输出中获取单词并找到任何带有字母Q的单词.如果单词确实如此,则需要将其替换为“bad”.之后,我试图将每个单词追加到output2.我这样做有困难.我编译时得到的错误是:
invalid conversion from ‘const char*’ to ‘char’ [-fpermissive]
#include <iostream>
#include <string>
#include <cstdlib>
#include <sstream>
using namespace std;
string manipulate(string x);
int main(int argc, char* argv[])
{
string input, temp, output, output2, test, test2;
int b;
cout << "Enter a string: ";
getline(cin, input);
istringstream iss(input);
while (iss >> test)
{
if(test.length() != 3)
{
test.append(" ", 1);
output.append(test);
}
}
istringstream iss2(output);
while (iss2 >> test2)
{
for(int i = 0; i<test2.length(); i++)
{
switch(test2[i])
{
case 'q':
test2[1]="bad";
output2.append(test2);
break;
}
}
}
cout << "Your orginal string was: " << input << endl;
cout << "Your new string is: " << output2 << endl;
cin.get();
return 0;
}
最佳答案
有更简单的方法如何做到这一点:
#include <iostream>
#include <string>
using namespace std;
int main()
{
string s("Your homework is bad. Really bad.");
while (s.find("bad") != string::npos)
s.replace(s.find("bad"), 3, "good");
cout << s << endl;
return 0;
}
输出:
Your homework is good. Really good.
这是一个没有调用查找超过我们需要的次数的示例:
size_t index;
while ((index = s.find("bad")) != string::npos)
s.replace(index, 3, "good");
第一个更容易阅读.
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转载注明原文:c – 尝试替换字符串中的单词 - 乐贴网